If it's not what You are looking for type in the equation solver your own equation and let us solve it.
6x^2-x-10x-10=0
We add all the numbers together, and all the variables
6x^2-11x-10=0
a = 6; b = -11; c = -10;
Δ = b2-4ac
Δ = -112-4·6·(-10)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-19}{2*6}=\frac{-8}{12} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+19}{2*6}=\frac{30}{12} =2+1/2 $
| 6x+5=2+19 | | -3n-6(n-6)=108 | | -129=2v-7(7-2v) | | 185=(-40-7n) | | -5(3r-1)=-85 | | 145=5(7+4x) | | 5(-3+6m)=-195 | | 4p-2=1680 | | 5k=+6k | | 6÷.25=y | | 6÷.25=x | | 10=3×(2+x) | | 4(3a+5)=92 | | q(q+11)+12(q+11)=0 | | 2a+50=a+200 | | (2x-1)^2-(3x+5)^2=0 | | 1,5x+3=6 | | 4g-4=-8 | | 5x(x-1)-(1-x)^2=0 | | 5x(x-1)-(1-x)=0 | | 3(m-6)=24 | | 6(1-2x)-4(x-2)=15 | | 2b-12=b-18 | | (4t+8)(2t-9)=0 | | 2x-3=x=4x-4 | | 5y+15=3y+75 | | R2h=3.14 | | 2y=y÷5+9 | | 2y×2y-2y(y-8)=13 | | (b-8)2= | | (b-8)²= | | -24=4(3x+3) |